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Mathematics · Oct / Nov 2022 · Paper 11 · Question 3

YMA01

As printed in the paper

The question as text

3. The share price of a company is monitored. Exactly 3 years after monitoring began, the share price was £1.05 Exactly 5 years after monitoring began, the share price was £1.65 The share price, £V, of the company is modelled by the equation V = pt + q where t is the number of years after monitoring began and p and q are constants.

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  • 3(a)[3]

    1.05

    =

    3p

    +

    q

    1.65

    =

    5p

    +

    q

    e.g. 2

    p =

    0.6

    or 1.05

    =

    3

    +

    (1.65

    −

    5 )

    or 1.65

    5

    (1.05

    3 )

    p

    p

    =

    p

    +

    −

    p

    =

    0.3

    =

    0.15

    p

    q

  • 3(b)[2]

    2.5

    =

    "0.3"

    +

    "0.15"

    =

    T

    T

    T =

    7.8

    (a)

    M1

    Forms two simultaneous equations (which may be in pence) and proceeds to find a value for

    p or q

    May be implied by a correct p or q (allow sight of 30 or 15).

    Also score for an attempt to calculate 1.65 1.05

    −

    or equivalent.

    5

    3

    −

    A1

    or

    oe

    p =

    0.3

    q =

    0.15

    A1

    p =

    0.3

    and

    q =

    0.15

    oe

    (b)

    M1

    Uses their values for p and q with

    V =

    2.5

    and rearranges to find a value for T. It must come

    from 2.5

    ±

    q

    which you may need to check on your calculator, allowing for truncation or

    p

    rounding (eg 8 following correct values for V, p and q)

    A1

    7.8 cao isw after sight of the correct answer.

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