Mathematics · May / June 2022 · Paper 51 · Question 2
YMA01
As printed in the paper
The question as text
2. A motorbike is moving with constant acceleration along a straight horizontal road. The motorbike passes a point P and 10 seconds later passes a point Q. The speed of the motorbike as it passes Q is 28 m s–1 Given that PQ = 220 m,
Read automatically from the paper; the printed page above is exact.
Show the answer and mark scheme
2(a)[3]
Other possible equations, any 2 of which could be used to obtain an
equation in a only:
28
10
=
u
+
a
(
u
+
28)
220
=
×
10
2
1
220
=
10
u
+
a
×
10
2
2
2
2
28
=
u
+
2
a
×
220
a = 1.2 (
m s−)
2
Any ONE of these:
28
=
+
1.2 6
×
=
20.8
u
u
4
4
28
=
+
1.2 5
×
=
22
u
u
5
5
1
s
=
16 4
×+
×
1.2 4
×
2
=
73.6
4
2
1
2(b)[4]
=
16 5
×+
×
1.2 5
×
2
=
95
s
5
2
Allow distances from Q
1
e.g.
s =
28 6
×−
×
1.2 6
×
2
=
146.4
6
2
1
s =
28 5
×−
×
1.2 5
×
2
=
125
5
2
1
1
e.g.
20.8 1
1.2 1
2
OR
22 1
1.2 1
2
s =
×+
×
×
s =
×−
×
×
2
2
OR
s =
95
−
73.6
OR
s =
146.4 125
−
22
2
=
20.8
2
+ ×
2 1.2s
OR
21.4 (m) Allow 21 (m).
Notes for question 2
N.B. Use of an incorrect suvat formula is M0.
M1 Complete method to find an equation in a only (note that u = 16)
1
1
N.B. Allow
(
for ‘reverse’
220
=
(28 10)
×
+
2 a
×
10
2
s
=
ut
+
at
2
2
motion) leading to a = 1.2 M1A0A0
2(a)
but if they then change a to 1.2, then it becomes M1A1A1
retrospectively)
M0 if they assume u = 0
A1 Correct equation
A1 cao
M1 Complete method to find the speed at t = 4 or 5
OR a distance at t = 4 or 5
2(b)
M0 if they assume u = 0
A1ft A correct speed or distance, follow through on their a and u but
only if u has been used to find a in part (a).
M1 Complete method to find the required distance
A1 cao
7400
−
200
−
6000
=
6000
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