Note AcademyNote Academy

Mathematics · Oct / Nov 2021 · Paper 51 · Question 1

YMA01

As printed in the paper

The question as text

1. A 2.5 m C D 2 m B 9 m Figure 1 A non‑uniform rod AB has length 9 m and mass M kg. The rod rests in equilibrium in a horizontal position on two supports, one at C where AC = 2.5 m and the other at D where DB = 2 m, as shown in Figure 1. The magnitude of the force acting on the rod at D is twice the magnitude of the force acting on the rod at C. The centre of mass of the rod is d metres from A. Find the value of d. (6)

Read automatically from the paper; the printed page above is exact.

Show the answer and mark scheme

2.5 m 4.5 m 2 m

A C G D B

d m Mg

1st Equation in d (or another defined unknown), R and M (as appropriate) only M1 A1

2nd Equation in d (or the same defined unknown, R and M (as appropriate)

only

Possible equations:

( ),

↑

R

+

2

R

=

Mg

M( ),2

C

R

×

4.5

=

Mg d

(

−

2.5)

M(

D R

),

×

4.5

=

Mg

(7

−

d

)

M( ),2.5

A

R

+

(7

×

2 )

R

=

Mgd

M( ),6.5

B

R

+

(2 2 )

×

R

=

Mg

(9

−

d

)

SC: M( ), (

G R d

−

2.5)

=

2 (7

R

−

d

)

Solve for d, must be a numerical value

d = 5.5

Notes for question 1

N.B. Allow M marks for equations if they use Rc and RD

M1 Correct number of terms, dimensionally correct, condone sign errors and

missing g

A1 Correct equation

M1 Correct number of terms, dimensionally correct, condone sign errors and

missing g

A1 Correct equation

DM1 Dependent on previous two M marks, for solving for d

A1 d = 5.5 oe Ignore an extra m (but not M)

N.B.

If g is omitted consistently in both equations, all three A marks are available.

If they use Rg consistently in both equations, all three A marks are available.

If they have 3 equations, mark the ones that are used to obtain d.

If R and 2R are consistently the wrong way round, apply the scheme, unless an

MR gives a better total.

3u 0

Make a free account to save your answers and see your weak topics and ask the AI why a wrong answer is wrong.