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Mathematics · Oct / Nov 2021 · Paper 11 · Question 3

YMA01

As printed in the paper

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  • 3(i)[3]

    3

    3

    (

    )

    x >

    4

    ⇒

    3

    x

    >

    4

    x

    2

    ⇒

    x

    4

    x

    −

    3

    <

    0

    ⇒

    0, 4

    3

    0

    <

    x

    <

    4

  • 3(ii)[3]

    y

    −

    0

    =

    3(

    x

    +

    5)

    E.g.

    y

    <

    2

    x

    2

    −

    50,

    y

    >

    3

    x

    +

    ''15''

    y

    <

    2

    x

    2

    −

    50,

    y

    >

    3

    x

    +

    15,

    x

    < −

    5

    E.g.

    (i)

    For the two critical values 0 and 3

    B1

    4

    M1

    Chooses the inside region for their critical values

    3

    3

    0

    <

    x

    <

    x >

    0

    x <

    A1

    Award for exact equivalents such as

    and

    or

    4

    4

    3

    x x

    :

    >

    0

    ∩

    x

    <

    4

    as 3

    3

    x >

    0

    x >

    4

    x <

    (Note they may deduce that

    then solve to find

    which combined

    4

    3

    gives

    0

    <

    x

    <

    )

    4

    ..........................................................................................................................................................

    B1: Sketches BOTH graphs. May only see right had

    branch of

    hyperbola.

    y =

    4

    M1: Chooses the inside region between 0 and

    their solution to 3

    4

    x =

    O

    3

    A1:

    0

    <

    x

    <

    4

    ..........................................................................................................................................................

    Special Case which is very common:

    3

    B1: States

    x <

    only

    4

    ..........................................................................................................................................................

    (ii)

    B1

    Correct equation for l E.g.

    y

    −

    0

    =

    3(

    x

    +

    5)

    . This may be implied by e.g. sight of y >

    3x + 15 or e.g. y = 3x + k and k = 15

    2

    M1

    Two of

    y

    <

    2

    x

    −

    50,

    y

    >

    3

    x

    +

    "15",

    x

    <

    a

    where

    −„

    5

    a

    „

    6.5

    Follow through their straight line provided it has a gradient of 3 with a numerical “15”.

    Also allow two of

    y

    „

    2

    x

    2

    −

    50,

    y

    …

    3

    x

    +

    15,

    x

    „

    a

    where

    −

    5

    „

    a

    „

    6.5

    3

    x

    +

    15

    <

    y

    <

    2

    x

    2

    −

    50 or 3

    x

    +

    15

    „

    y

    „

    2

    x

    2

    −

    50

    Also allow

    as 2 inequalities.

    2

    Do not allow inequalities in terms of R e.g.

    R

    <

    2

    x

    −

    50,

    R

    >

    3

    x

    +

    15.

    This scores

    M0.

    A1

    Fully defines region. E.g.

    y

    <

    2

    x

    2

    −

    50,

    y

    >

    3

    x

    +

    15,

    x

    <

    a

    where 5

    −„

    a

    „

    6.5

    y

    „

    2

    x

    2

    −

    50,

    y

    …

    3

    x

    +

    15,

    x

    „

    a

    where 5

    −„

    a

    „

    6.5

    Also allow

    If set notation is used, then they must use “∩” between any of their inequalities rather

    than “∪”.

    Condone attempts as long as the intention is clear.

    E.g.

    {

    } {

    x y

    ,

    ∈

    :

    y

    <

    2

    x

    −

    50

    ∩

    y

    >

    3

    x

    +

    15

    ∩

    x

    <

    a

    ,

    x y

    ,

    ∈

    :

    y

    <

    2

    x

    −

    50,

    y

    >

    3

    x

    2

    2

    are acceptable.

    Note regarding consistency for the A1 if −5 is used:

    y

    <

    2

    x

    2

    −

    50,

    y

    >

    3

    x

    +

    15

    must go with x < −5

    2

    y

    „

    2

    x

    −

    50,

    y

    …

    3

    x

    +

    15

    must go with x „ −5

    If

    −

    5

    <

    a

    „

    6.5

    is used then x

    <

    a

    or x

    „

    a

    is acceptable.

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