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Mathematics · May / June 2021 · Paper 31 · Question 1

YMA01

As printed in the paper

The question as text

1. The curve C has equation y = x 2 cos 1   2 x  0 < x  π  The curve has a stationary point at the point P.

Read automatically from the paper; the printed page above is exact.

Show the answer and mark scheme
  • 1(a)[4]

    d

    y

    1

    1

    1

    =

    2 cos

    x

    x

    −

    x

    sin

    x

    2

    d

    x

    2

    2

    2

    Sets d

    y

    1

    4

    4

    =

    0

    ⇒

    tan

    x

    =

    ⇒

    x

    =

    2arctan

    *

    d

    x

    2

    x

    x

  • 1(b)[3]

    4

    x

    =

    2arctan 2

    2

    awrt 2.214

    x =

    2.155

    x =

    cao

    2

    6

    (a)

    1

    M1: Differentiates using the product rule to obtain an expression of the form

    Ax

    cos

    x

    +

    Bx

    2

    If the product rule is quoted it must be correct.

    A1: For a correct simplified or unsimplified derivative.

    dM1: Sets their d

    y

    1

    x =

    0

    and proceeds to an equation involving

    tan 2 x

    . This may be implied by their working.

    d

    The M1 must have been scored.

    4

    A1*: Correctly achieves the given answer of

    x

    =

    2arctan

    x

    1

    sin 2

    x

    1

    =

    4

    2

    x

    tan 2 x

    =

    An intermediate line of

    or

    must be seen

    x

    1

    1

    x

    2

    cos

    x

    2

    2

    Note that some may work backwards having differentiated e.g.

    ( )

    4

    x

    4

    x

    4

    x

    sin

    x

    x

    x

    x

    =

    2arctan

    ⇒

    =

    arctan

    ⇒

    tan

    =

    ⇒

    2

    =

    4

    ⇒

    4cos

    =

    x

    sin

    x

    2

    x

    2

    x

    cos

    ( )

    2

    2

    x

    2

    x

    1

    x

    x

    1

    x

    ⇒

    2 cos

    x

    =

    x

    2

    sin

    ⇒

    2 cos

    x

    −

    x

    2

    sin

    =

    0

    2

    2

    2

    2

    2

    2

    Score M1 for a complete method to reach d

    y

    and A1 if correct with (minimal) conclusion.

    x =

    0

    d

    (b)

    4

    M1: Attempts to use the given iteration formula. Award for

    x

    =

    2arctan 2

    or awrt 2.21

    2

    Note that this mark may also be implied by awrt 127 if they are using degrees and no working is shown.

    2x = awrt 2.214

    A1:

    6x = 2.155 (Note that this is not awrt)

    A1:

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