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Mathematics · Oct / Nov 2020 · Paper 41 · Question 5

YMA01

As printed in the paper

The question as text

5. y R O 2 4 x Figure 3 ln x ∫

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  • 5(a)[3]

    d

    x

    =

    x

    −

    2

    ln

    x x

    d

    = −

    x

    −

    1

    ln

    x

    +

    x

    −

    1

    ×

    d

    x

    x

    2

    x

    = −

    x

    −

    1

    ln

    x

    −

    x

    −

    1

    (

    +

    c

    )

    3

    +

    2

    x

    +

    ln

    x

  • 5(b)[4]

    =

    3

    x

    −

    2

    +

    2

    x

    −

    1

    +

    x

    −

    2

    ln

    x

    oe

    x

    2

    4

    3

    ln

    x

    1

    Area =

    −

    +

    2ln ''

    x

    −

    −

    ''

    x

    x

    x

    2

    3

    ln 4

    1

    3

    ln 2

    1

    = −

    +

    2ln 4

    −

    −

    −−

    +

    2ln 2

    −

    −

    =1

    2ln 2

    +

    4

    4

    4

    2

    2

    2

    (a)

    ∫

    ∫

    1

    M1: Attempts by parts to reach a form

    x

    −

    2

    ln

    x x

    d

    ax

    −

    1

    ln

    x

    b

    x

    −

    1

    d

    x

    where ,

    = ±

    ±

    ×

    a b ≠

    x

    If a formula is stated it must be correct.

    dM1: Integrates again to reach a form

    ±

    ax

    −

    1

    ln

    x

    ±

    bx

    −

    1

    ln

    x

    1

    A1:

    −

    x

    −

    1

    ln

    x

    −

    x

    −

    1

    (

    +

    c

    )

    o.e such as

    −

    −

    +

    c

    x

    x

    (

    )

    Condone the omission of the constant of integration. Condone

    −

    x

    −

    1

    ln

    x

    + −

    x

    −

    1

    (b)

    3

    +

    2

    x

    +

    ln

    x

    3

    2

    ln x

    B1:

    =

    3

    x

    −

    2

    +

    2

    x

    −

    1

    +

    x

    −

    2

    ln

    x

    or

    +

    +

    .

    x

    2

    x

    2

    x

    x

    2

    The 2

    ∫

    2

    x

    may be implied by later work. That is if they state

    d

    2ln

    or

    ln x

    2

    x

    =

    x

    x

    x

    2

    4

    3

    ln

    x

    1

    M1: Area =

    2ln ''

    x

    ''

    following through on their part (a)

    −

    +

    −

    −

    x

    x

    x

    2

    p

    ln

    x

    s

    4

    M1: For substituting 2 and 4 into an expression of the form

    +

    q

    ln

    x

    +

    r

    +

    and attempts to

    x

    x

    x

    2

    simplify by using one log law correctly. (Note that the two terms in 1

    x may be combined before substitution)

    A1: Exact answer: Likely to be 1

    or 1

    +

    2ln 2

    +

    ln 4

    ........................................................................................................................................................................

    For those who don't read the instruction in (b) to use (a) and do via parts score

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