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Mathematics · Oct / Nov 2020 · Paper 31 · Question 2

YMA01

As printed in the paper

The question as text

2. A scientist monitored the growth of bacteria on a dish over a 30‑day period. The area, N mm2, of the dish covered by bacteria, t days after monitoring began, is modelled by the equation log10 N = 0.0646 t + 1.478 0  t  30

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  • 2(a)[4]

    10

    1.478

    10

    0.0646

    10

    0.0646

    t+

    1.478

    Sight of

    or

    or

    (

    )awrt 30

    or (

    )awrt 1.16

    a =

    b =

    0.0646

    t

    +

    1.478

    0.0646

    t

    1.478

    log

    N

    =

    0.0646

    t

    +

    1.478

    →

    N

    =

    10

    =

    10

    10

    10

    t

    =

    "30

    "

    ×

    "1.16

    "

    t

    N =

    30 1.16

    ×

    30

  • 2(b)[2]

    Attempts

    N =

    30 1.16

    ×

    =

    awrt 2600

    (a)

    NB This shows as MMAA on ePEN but is being marked as MAMA.

    M1

    Sight of

    10

    1.478

    or

    10

    0.0646

    or

    10

    0.0646

    t+

    1.478

    (allowing slips copying the values) anywhere in their solution.

    This mark is implied by seeing awrt 30 or awrt 1.16

    Sight of either awrt 30 or awrt 1.16

    A1

    (

    )

    t

    0.0646

    1.478

    dM1

    Applies correct index laws and proceeds to find values for a and b.

    N

    =

    10

    ×

    10

    =

    10

    0.0464

    t+

    For this mark there must be evidence of correct index work so expect to see at least

    answer and no incorrect index work.

    A1

    a

    =

    awrt

    30

    and

    b

    =

    awrt

    1.16

    as long as there is no contrary work, or states that

    N =

    30 1.16

    ×

    (b)

    30

    N =

    30 1.16

    ×

    M1

    Attempts

    with their values of a and b.

    3.416

    log

    N

    =

    0.0646 30 1.478

    ×

    +

    ⇒

    N

    =

    10

    Alternatively

    10

    A1

    awrt 2600, isw after a correct answer.

    ...................................................................................................................................................................................

    t

    N

    =

    ab

    Alt (a) using

    as a starting point.

    M1

    As main scheme.

    a =

    awrt 30

    b =

    awrt 1.16

    A1

    or

    (must be correctly assigned)

    dM1

    Takes

    log

    of both sides and proceeds to at least

    log

    N

    =

    log

    a

    +

    t

    log

    b

    and attempts to find a value for

    10

    10

    10

    10

    both of the constants with no incorrect log work.

    A1

    a

    =

    awrt

    30

    and

    b

    =

    awrt

    1.16

    as long as there is no contrary work, or states that

    N =

    30 1.16

    ×

    1

    1

    (

    )

    (

    )

    (

    )

    4

    x

    −

    1

    × −

    2

    2

    x

    +

    3

    ×

    2 4

    x

    −

    1

    −

    d

    y

    2

    2

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