Mathematics · Oct / Nov 2020 · Paper 21 · Question 2
YMA01
As printed in the paper
The question as text
2. x 2 y = x 2 + ( 5 3 )
Read automatically from the paper; the printed page above is exact.
Show the answer and mark scheme
2(a)[1]
x
− 0.25
0
0.25
0.5
0.75
y
0.462
0.577
0.653
0.686
0.698
Allow awrt these values and look for the values appearing in the body of the script or within
their calculation in part (b).
Also allow exact value for the 0.577 e.g. 1
3
or 3
3
2(b)[3]
Correct strip width. May be implied
by 1
or 1
h =
0.25
×
0.25
8
2
1
{
}
(
)
A ≈
×
"0.25" 0.462
+
0.698
+
2 "0.577" 0.653 "0.686"
+
+
2
Correct application of the trapezium rule with their h
Must be a correct application of the rule so e.g.
1
(
)
A ≈
×
"0.25" 0.462
×
+
0.698
+
2 "0.577" 0.653 "0.686"
+
+
2
Scores M0 unless any missing brackets are implied by subsequent work.
1
{
(
)
×
"0.25" 0.462
+
0.698
+
2 "0.577" 0.653 "0.686"
+
+
A ≈
2
Would also score M0 unless the closing bracket was implied by subsequent work
Condone copying slips e.g. 0.426 instead of 0.462.
Must use all the yvalues. Repeated or missing yvalues scores M0.
Allow separate trapezia e.g.
1
1
1
1
(
)
(
)
(
)
(
)
A ≈
×
"0.25" 0.462
+
"0.577"
+
×
"0.25" "0.577" 0.653
+
+
×
"0.25" 0.653 "0.686"
+
+
×
"0.25" "0.686" 0.698
+
2
2
2
2
Allow use of the function e.g.
1
2
−
0.25
2
0.75
2
0
2
0.25
2
0.5
A
≈
×
0.25
+
+
2
+
+
2
5( 0.25)
−
2
+
3
5(0.75)
2
+
3
5(0)
2
+
3
5(0.25)
2
+
3
5(0.5)
2
+
3
= awrt 0.624 or 78
oe e.g. 312
accept awrt 0.624 or exact fraction
but isw if necessary
125
500
Note that the calculator answer for the integral is 0.6265569683…
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