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Mathematics · May / June 2026 · Paper 43 · Question 12

0580

As printed in the paper

Show the answer and mark scheme
  • 12(a)[2]

    Correct sketch to go through (0, 1), (90, 0), (270, 0) and (360, 1) [2]

    For 1 or 2 marks, ignore any sketch outside For 2 marks, correct curve starting at (0, 1), passing through (360, 1) and (180, –1), and reasonably close to (90, 0) and (270, 0) with correct curvature.

    B1 for correct shape starting at (0, 1) but For B1 mark the intention by eye. Award B1 if the ‘curve’ includes straight lines or inaccurate at roots and/or max/min. Needs at least one complete cycle, but may have more has a vertex at min but all other features correct. than one. For more than one cycle, must have consistent amplitude (check by eye) Ruled graphs score 0. or for starting at (0, 1) with all roots and max/min correct but some incorrect curvature.

  • 12(b)[3]

    109.5 and 250.5 [3]

    Mark at most accurate. If more than two solutions, mark the worst two. 109 or 109.47… and 251 or 250.53 or 250.52…

    B2 for 1 correct 1

    Or M1 for cos = − oe M1 implied by 109 not as answer. 3 If M1 or 0 scored, and only 2 angles given, SC1 Not multiples of 90. if they add to 360

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