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Mathematics · May / June 2026 · Paper 22 · Question 23

0580

As printed in the paper

The question as text

The equation of a curve is y x x 2 11 12 2 ¢ Á È .

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  • 23(a)[3]

    –3 [8]

    Condone answer –3x for B2 3 Do not allow answer y = –3 for 3 marks.

    B2 for 4x – 11 isw Condone poor notation for derivative e.g.

    B2 for y = 4x – 11, 0 = 4x – 11, 2 = 4x – 11, similarly

    or B1 for 4x – k or kx – 11 or for B1 4x – 11 + 12 isw

  • 23(b)[4]

    y = 1 8 − or 3y – x + 8 = 0 oe x 3 3 [4]

    For 4 marks, like terms must be collected. Allow equivalent fractions or exact decimals, e.g. 2 8 & − − − − 2 3 or 2.6, 2.6r for but not rounded 3 decimals such as 2.67, 0.333… 1 8

    B3 for 1 8 = + − x − or oe e.g.

    B3 for y x 3 3 3 3 = − Award

    B3 for y 0.333 x 2.67 . (y – –2) = ( 1 ) − x 2 oe B1 may be implied by (2, –2) or 3 –2 = (their m)x + c. OR

    B1 for y = –2 This mark must be scored in part (b) workspace.

    M1 for gradient = 1 1 −their a 3 or If their (a) is kx, condone

    M1 for ( ) 1 −their k . gradient =

    M1 for substituting (2, – 2) or their –2 should be the result of evaluating (2, their –2) into 2(2)2 – 11 × 2 + 12 this working may be seen in y = (their m)x + c oe part (a). ( ) oe e.g. (y – (their –2)) = − their m x 2 , ( ) − − y their 2 their m = , their m cannot be their (a) − x 2

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