Mathematics · May / June 2026 · Paper 22 · Question 14
0580
As printed in the paper
Show the answer and mark scheme
14(a)[2]
–2 1 6 [2]
B1 for one correct value in the Numbers must be in the correct order. correct position OR
SC1 for answer –3 –2 1
14(b)[2]
4 × 3n – 1 oe final answer [2]
For 2 marks (or 1 if spoilt) equivalents include 3 n 12 × 3n – 2, 3n + 3n – 1 , × . 4 3 16 128 − + − Allow n 3 24 n 2 n 20 . 3 3 Allow other variables for n. Condone e.g. n = 4 × 3n – 1.
B1 for [c ×] 3an + k oe, a > 0
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