Mathematics · May / June 2026 · Paper 21 · Question 11
0580
As printed in the paper
Show the answer and mark scheme
11(a)[3]
2n + 1 oe final answer [7]
3n – 4 – (n – 5) scores 3 marks. 3
B2 for 3n – 4 for sequence C
or B1 for 3n + j or kn – 4, k ≠ 0 for sequence C,
or M1 for their nth term – (n – 5) their nth term must be equivalent to the form an + b. OR
B2 for 5, 7, 9 for sequence A
or B1 for –3, –2, –1 for sequence B
11(b)(i)[1]
16 [1]
11(b)(ii)[2]
2n – 2 oe final answer [2]
For 2 marks (or 1 if spoilt) equivalents include 2 − n n , 1 1 2 2 (2)n – 1, . 4 2 Allow other variables for n. − = n 2
B1 for [c ×] 2an + k, a > 0 Condone e.g. n 2 k an − or for [ ]1 × c , a > 0 2
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