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Mathematics · Oct / Nov 2025 · Paper 22 · Question 20

0580

As printed in the paper

The question as text

( )x x 2 1 21 f Ÿ Á , x 2 1 ¼ ( )x x 3 4 g Ÿ È

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Show the answer and mark scheme
  • 20(a)(i)[1]

    10 [1]

  • 20(a)(ii)[2]

    –17 [1]

    M1 for g(–7) oe 2 + 21 or 3 4 oe soi − 2 1 x

  • 20(a)(iii)[3]

    21 + x or 21 1 x + oe final answer 2 x 2 2 [3]

    M2 for one step from answer + y e.g. x = 21 or x = 21 1 + 2 y 2 y 2 21 = + or 2 y 1 x + 21 x = or 2xy = 21 + x or 2 y x

    or M1 for correct first step e.g. 21 x = or better − 2 y 1 or y (2x – 1) = 21 or better

  • 20(b)[5]

    5 5 − 3 and oe 2 [5]

    B3 for 6x2 + 5x – 25 [= 0]

    or M1 for 21 = (2x – 1)(3x + 4) oe

    B1 for 6x2 – 3x + 8x – 4 or better and

    M1 for correct method to solve their three-term quadratic e.g. (3x – 5)(2x + 5) [= 0] −± −××− 5 5 4 6 25 2 or oe 12

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