Mathematics · Oct / Nov 2024 · Paper 42 · Question 4
0580
As printed in the paper
Show the answer and mark scheme
4(a)[2]
135 [2]
M1 for 360 × k, where k = 1, 3 or 5 oe + 5 3
4(b)(i)[2]
26 [2]
B1 for ∠ABD = 49
4(b)(ii)[1]
86 [2]
B1 for ∠QAD = 49 or for ∠BDA = 45 or for ∠BCA = 45 Angle in a semicircle = 90 [1]
4(c)(i)[3]
− 1 6.75 [2 × ] cos oe 11.5 108.117… [4]
M2 M1 for cos(…) = 6.75 11.5 oe A1
4(c)(ii)[2]
12.7 or 12.73 to 12.74 [2]
M1 for 108.12 × 2 × π × 6.75 360
4(c)(iii)[3]
100 or 100.1 to 100.2 [3]
−
M2 for 360 108.12 × π × 6.752 oe 360
or M1 for 108.12 × π × 6.752 360 − If 0 scored,
SC1 for 360 108.12 × π × k 360
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