Mathematics · May / June 2024 · Paper 42 · Question 2
0580
As printed in the paper
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2(a)[2]
142 142 [2]
B1 for each FT angle b = their angle a
2(b)[2]
150 [2]
M1 for 360 12 oe isw ( ) × − or 180 12 2 oe isw
2(c)[3]
56 34 [4]
B1 B2 M1 for angle at centre = 2 × their 56 oe soi or for angle OMB = 90 oe soi
2(d)[2]
51 [2]
B1 for opp angle = 129 soi
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