Mathematics · May / June 2024 · Paper 42 · Question 11
0580
As printed in the paper
Show the answer and mark scheme
11(a)[2]
–4 (–1)3 – 9 (–1)2 + 5 or better = 0 [so stationary point] [2]
M1 A1 with no errors
11(b)(i)[3]
18 [3]
B2 for − 6 x 2 6 isw OR 2 + 2 −
B1 for 6 x k (any k) isw or px 6 isw (p ≠ 0) − or 6 x 2 6 + 8 M1dep on
B1 for x = −2 substituted into their d y x d
11(b)(ii)[2]
1 and –1 [2]
M1 for 6 x 2 − 6 = 0 oe seen or for their d y x = 0 if B1 scored in part d (b)(i)
Make a free account to save your answers and see your weak topics and ask the AI why a wrong answer is wrong.