Mathematics · May / June 2024 · Paper 41 · Question 3
0580
As printed in the paper
Show the answer and mark scheme
3(a)(i)[2]
80 [2]
M1 for 1 4 ×× 2 5 8
3(a)(ii)[2]
5 [1]
× 2
M1 for 15 4 2 = [ y ] 2.4 oe
3(b)[3]
+ + 5 x 23 5 x 23 or final − + + − ( x 1)(2 x 5) 2 x 2 3 x 5 answer [3]
B1 for 4(2x + 5) –3(x – 1) oe isw
B1 for common denominator = (x – 1) (2x + 5) oe isw
3(c)[3]
2x3 –13x2 + 8x + 48 final answer [3]
B2 for correct expansion of 3 brackets but unsimplified or for simplified four-term expression of correct form with 3 terms correct
or B1 for correct expansion of two brackets with at least 3 terms out of 4 correct
3(d)[3]
8x 12 − or 8 x y 12 6 final answer 6 y [3]
B2 for two elements correct in final answer or for correct answer seen then spoiled or for correct expression where all parts of the power have been dealt with 3 4 2 x or for () − 1 or y 2
or B1 for 8 or y6 or − 6 or x12 correct in y final answer 3 − 3 16 x 16 y 2 4 or for or 8 4 y 2 x
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