Mathematics · May / June 2023 · Paper 41 · Question 3
0580
As printed in the paper
Show the answer and mark scheme
3(a)(i)[4]
55.87 [4]
M1 for midpoints soi
M1 for use of fm where m is in the correct interval including boundaries M1 (dep on 2nd M1) for fm ÷1000
3(a)(ii)[2]
177 500 cao [1]
+ 2
M1 for 154 200 oe 1000
3(b)(i)[1]
25000 [1]
3(b)(ii)[1]
× 2.473 10 4 [1]
3(c)(i)[3]
166 650 or 165816 nfww [3]
M2 for (500 + 5) × ‘320 to 340’ or ‘500 to 510’ × (320 + 10)
or M1 for 500 − 5 or 500 + 5 or 320 10 − or + 320 10 Alternative method
M2 for 504 × ‘320 to 340’ or ‘500 to 510’ × 329
or M1 for 504 or 329
3(c)(ii)[2]
285 or 286 nfww [1]
− 2
M1 for 800 10
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