Mathematics · May / June 2023 · Paper 41 · Question 1
0580
As printed in the paper
Show the answer and mark scheme
1(a)(i)[2]
600 [2]
M1 for 1250 4 × k where k = 1, 4, 9, 12 oe + + 12 9
1(a)(ii)[2]
80 [2]
M1 for 1250 × 64 [÷ 1000]
1(a)(iii)[2]
60 [2]
10 × − =
M1 for x 1 54 oe 100
1(a)(iv)[2]
1000 [2]
M1 for 1250 – (1250 ÷ 5) oe
or B1 for 250
1(b)(i)[2]
3.52 [2]
M1 for [10 –] 12 × 0.54
or B1 for 6.48
1(b)(ii)[3]
0.08 [3]
B2 for 0.077[4...]
or M1 for 0.51 ÷ 0.826 If 0 or 1 scored award instead
SC2 for 0.93 final answer OR If 0 scored
SC1 for 0.06 as answer
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