Mathematics · Oct / Nov 2022 · Paper 42 · Question 6
0580
As printed in the paper
Show the answer and mark scheme
6(a)[2]
–1.5 or –1 1 2 or – 3 2 [2]
M1 for 4x = 9 – 15 or x + 15 4 = 9 4
6(b)[1]
(a – 3)(a + 3) final answer [1]
6(c)[3]
8 c d final answer 3 [3]
B2 for 8 ad or 40 ac c d 3 15 or 4 ×c 2 seen 1 3 d or for correct answer seen then spoiled
or M1 for 4 a 10 ad or 8 c ac 3 ad × ÷ oe 5 3 10 c 10 c
6(d)[2]
n + 1 final answer [2]
M1 for 5 5 × n or 5n+1 seen
6(e)[3]
(2x – 1)(2x + 5) [= 0] oe 1 2 or 0.5 and –2.5 or –2 1 2 or – 5 2 [4]
B2 M1 for 2x(2x + 5) – [1](2x + 5) [ = 0] or 2x(2x – 1) + 5(2x – 1) [ = 0] or for (2x + m)(2x + n) [ = 0] with and mn = –5 or n + m = 4 B1
6(f)(i)[3]
7 [3]
M1 for y = k(x + 3)3 or better
M1 for 108 = their k(x + 3)3
6(f)(ii)[2]
4 [2]
2 1
M1 for oe 2 k or oe seen or better 1 d 2 4
6(g)[3]
2x3 + 7x2 – 9 final answer [3]
B2 for correct expansion unsimplified or for simplified 4 term expression of correct form with 3 terms correct
or B1 for one pair of brackets expanded with at least 3 terms out of 4 correct
6(h)[2]
6x + 4 [2]
B1 for 6x or 4 or 6x + 4 with one extra term seen
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