Mathematics · Oct / Nov 2022 · Paper 42 · Question 10
0580
As printed in the paper
Show the answer and mark scheme
10(a)[2]
42.05 final answer [2]
M1 for 11.4 + 0.05 oe or 14.8 + 0.05 oe or 15.7 + 0.05 oe
10(b)[2]
319 or 318.5 to 318.6 [2]
M1 for 150 × π × 2 15.6 oe 360
10(c)[4]
360 − x x × r + 2r = 3 × 2 π r + 2 r oe 2π 360 360 4 x × 2π[r ] = 2π[r] – 4[r] oe 360 ( ) 90 π − 2 Leading to π [5]
M2 x × 2πr oe seen
M1 for 360 or − 360 x × 2π r oe seen 360 M1 i.e. M mark for isolating and collecting terms in x A1 With no errors or omissions
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