Mathematics · Oct / Nov 2022 · Paper 41 · Question 1
0580
As printed in the paper
Show the answer and mark scheme
1(a)(i)[2]
1580 or 1583 to 1584 [2]
M1 for π × 6 2 × 14
1(a)(ii)[2]
452 or 452.3 to 452.4... [2]
× 1 4
M1 for × π × 6 3 2 3
1(b)(i)[1]
7.85 ÷ 1000 [= 0.00785] [1]
M1
1(b)(ii)[2]
16[.0] or 15.95 to 15.99 [2]
FT {their (a)(i) + their (a)(ii)} × 0.00785 evaluated to 3 sig fig or better
M1 for (their (a)(i) + their (a)(ii)) × 0.00785
1(c)(i)[3]
16.2 or 16.21 to 16.23 [3]
4 − × ×× 3 2000 50 π 2 3 [ ]
M2 for × 100 2000 4 × ×× 3 50 π 2 3 or for × 100 2000 4 × ×× 3 50 π 2 3
or M1 for 2000
1(c)(ii)[1]
6.87 or 6.870 to 6.872 [1]
4 − × ×× 3 FT 2000 their 50 π 2 3 3 evaluated to 3sf or better
1(d)[4]
2 3 oe [4]
M1 for 2 [π](3 ) R + [π]3 R × 9 R oe
M1 for 2[π] x 2 + 2[π] x × 7 x oe
M1 for their area of cone = their area of cylinder seen
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