Mathematics · May / June 2022 · Paper 42 · Question 11
0580
As printed in the paper
Show the answer and mark scheme
11(a)(i)[2]
4.455 to 4.456… [= 4.46] [2]
M1 for [r =] 28 2π oe
11(a)(ii)[2]
1250 or 1247 to 1249.9… [2]
M1 for 20 ×π× 4.46 2 oe
11(a)(iii)[3]
66[.0] or 65.95 to 66.02 [3]
M2 for [tan] = 20 oe × 2 4.46
or B1 for identifying angle ANB on cylinder not on rectangle
11(b)[5]
11.8 or 11.82 to 11.83 [5]
× 3 310 3 =
M2 for [ r ] oe 2π 3 310 3 4 ×× = or [ h ] oe π = π × 2 ×
or M1 for 310 1 r 2 r 3 2 1 h = π or 310 h 3 2 ( ) 2 + × 2
M2 for ( their r ) 2 their r oe ( ) ( ) 2 = 2 + × 2
or M1 for [ l ] their r 2 their r oe
Make a free account to save your answers and see your weak topics and ask the AI why a wrong answer is wrong.

