Mathematics · Oct / Nov 2021 · Paper 42 · Question 6
0580
As printed in the paper
Show the answer and mark scheme
6(a)(i)[3]
4.5, 4 1 2 or 9 2 [3]
M1 for 8x – 12 = 24 or 2x – 3 = 6
M1 for reaching ax = b correctly FT their first step
6(a)(ii)[2]
4 or x > –11 − x > 3 final answer 3 [2]
M1 for 6x > 6 – 14 or x + 14 6 > 1
6(b)[3]
3 2 x 3 − V oe final answer [y =] 3 [3]
M1 for isolating term in y
M1 for division by 3 or FT their first step
M1 for cube root or FT their previous step to the final answer
6(c)[3]
4n2 – 20n + 12 4(n2 – 5n + 3) or correct explanation linked to expression [4]
M2 B1 for 4n2 – 10n – 10n + 25 A1 with no errors seen e.g. 4, [–]20 and 12 are all multiples of 4 or divides each term or each coefficient by 4
6(d)(i)[3]
p = –3 and q = 23 [3]
B2 for 23 – 2(x –3)2 OR
M1 for [q] – 2x2 – 4px – 2p2 or –2(x – 3)2 seen
B1 for either p = –3 or q = 23 or FT q = 5 + 2(their p)2
6(d)(ii)[1]
(3, 23) [1]
FT their (d)(i)
6(e)[2]
69 [2]
M1 for figs 132 oe
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