Mathematics · May / June 2021 · Paper 42 · Question 3
0580
As printed in the paper
Show the answer and mark scheme
3(a)(i)[1]
711 cao [1]
3(a)(ii)[1]
710 cao [1]
3(a)(iii)[1]
72 cao [1]
If answers 11, 10 and 2 in (a) then allow SC1 in this part
3(b)[3]
1000x9y12 final answer [3]
B2 for correct answer seen or answer of the form 1000x9yk or 1000xky12 or kx9y12
or B1 for answer with one correct element in product or (10x3y4)[3] seen
3(c)(i)[2]
108 [2]
M1 for [540 =] 22 [×] 33 [×] 5
or B1 for 108 oe not in prime factor form e.g. 22 × 3 × 9
3(c)(ii)[2]
30 240 [2]
M1 for (540 × 25 × 33 × 7) ÷ their (c)(i) oe
or B1 for answer 30 240 oe not in prime factor form e.g. 25 × 33 × 35
3(c)(iii)[2]
98 [2]
B1 for 592 704 seen or 26 × 33 × 73 seen or 2 × 72 oe seen
3(d)(i)[2]
(x – 7) (x + 4) final answer [2]
M1 for x(x – 7) + 4(x – 7) or x(x + 4) – 7 (x + 4) or better or for (x + a)(x + b) where ab = – 28 or a + b = – 3
3(d)(ii)[2]
(a + 2b)(11a + 14b) final answer [2]
M1 for (a + 2b) (7(a + 2b) + 4a) or (a + pb)(11a + qb) where pq = 28 or 11p + q = 36 If 0 scored,
SC1 for a + 2b (11a + 14b)
3(e)[4]
5 x − 1 [ y = ] oe final answer 2 [4]
B2 for 2x – 1 = –2x + 2y – x oe
or B1 for 9x = 32x or better M1dep for correct rearrangement of their 5 term ‘linear’ equation in y and x to make y the subject
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