Mathematics · May / June 2021 · Paper 41 · Question 11
0580
As printed in the paper
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11(a)[2]
20 [2]
M1 for 360 16 180 × − 18 or 180 18
11(b)[2]
4.5 [2]
M1 for BE = 5.2 oe 6.75 5.2 + 2.6
11(c)[3]
5.8[0] or 5.798 to 5.799 [3]
3 780 ×
M2 for 2 oe 32 3
or M1 for 3 780 32 or 3 32 2 32 780 or = l 3 780
11(d)[4]
QN = NR [given] Two correct pairs of angles with reasons from angle PQN = angle SRN alternate angle QPN = angle RSN alternate angle PNQ = angle SNR [vertically] opposite ASA [implies congruent] [8]
B1 B2 B1 for any correct pair of angles with reason or two correct pairs of angles with no/wrong reasons B1 dep on B1 B2
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