Mathematics · May / June 2021 · Paper 21 · Question 16
0580
As printed in the paper
The question as text
y x 5 4 3 2 1 0 – 1 – 1 6 5 4 3 2 1 – 2 – 3 – 2 – 3 l
Read automatically from the paper; the printed page above is exact.
Show the answer and mark scheme
16(a)[2]
– 3 4 or − 0.75 [2]
M1 for correct rise over run
or B1 for answer 3 4 oe
16(b)[2]
3 [ y = − ] x + 2 oe 4 [2]
FT [ y = ] their (a) x + 2 oe
B1 for [ y = ] their (a) x + c or [ y = ] mx + 2 .
16(c)[3]
] 4 [ y = x − 23 oe 3 [3]
M1 for gradient − 1 (a) their
M1 for (12, − 7) substituted into y = their mx + c
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