Mathematics · Oct / Nov 2020 · Paper 41 · Question 4
0580
As printed in the paper
Show the answer and mark scheme
4(a)[3]
38.6 [3]
M2 for [2 ×] (8.5 + 0.05 + 10.7 + 0.05)
or M1 for 8.5 + 0.05 or 10.7 + 0.05
4(b)(i)[2]
8.86 or 8.863… [2]
M1 for 9 h = sin 80 or better oe
4(b)(ii)[2]
∠CDF = 100 leading to ∠DCF = 40 Or ∠EDF = 80 leading to ∠DCF = 40 ‘two equal angles’ [2]
M1 Implied by 180-(100 + 40) = 40 or 80 – 40 A1 With no incorrect work seen
4(b)(iii)[3]
66.5 or 66.45 to 66.47… [3]
M2 for 0.5(3 + 12) × their (b)(i) or 12 × their (b)(i) – 0.5 × 9 × 9 × sin 100 oe
or B1 for DC = 9 or BC = 3
4(c)[5]
130 nfww or 129.6 to 129.8 [5]
B1 for ∠ACD = 21º or ∠CAD = 69º Method 1
M2 for cos 21 = 12 AC oe
or M1 for ∠ADC = 90 soi
M1 for π(their AC/2)2 OR Method 2 12 r
M2 for = oe sin 138 sin 21
or M1 for ∠COD = 138 soi
M1 for π ( their r ) 2 OR Method 3
M2 for cos 21 = 6 OC oe
or M1 for ∠CXO = 90 soi where X is the point where the perpendicular from O meets the chord CD
M1 for π ( their OC) 2
4(d)[3]
78.4 or 78.37 to 78.41 [3]
M2 for x × 2 × π × 9.5 + 2 × 9.5 = 4 × 8 oe 360 x × 2 × π × 9.5
or M1 for 360 After M0,
SC1 for 9.5x + 19 = 32 oe
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