Mathematics · Oct / Nov 2020 · Paper 41 · Question 10
0580
As printed in the paper
Show the answer and mark scheme
10(a)(i)[4]
A(–4, 0) B(1, 0) C(0, –4) [4]
B3 for A and B correct
Or B2 for B (–4, 0) and A (1, 0)
Or B1 for (x + 4)(x – 1) or for 2 −± 3 3 −× ×− 4 1 4 oe 2 and
B1 for A or B correct
B1 for C(0, –4) OR
SC2 for –4, 1 and –4 in correct positions on the graph
10(a)(ii)[2]
2x + 3 [ ± 0] final answer [2]
B1 for answer 2x +c or for ax + 3, a ≠ 0 or for correct answer seen
10(a)(iii)[3]
y = 7x – 8 oe [3]
B2 for answer 7x – 8 OR
M1 for [gradient =] 2(2) + 3 FT their part (a)(ii) of the form ax + b M1dep for substitution of (2, 6) into y = their mx + c oe
10(b)(i)[2]
Correct sketch 0 90 180 270 360 [2]
B1 for one correct section out of 4 OR
B1 for two properties correct from
Crosses x-axis at (0, 0) (180, 0) and (360, 0) only Correct curvature in each section of 90oAsymptotes at x = 90 and x = 27010(b)(ii)[3]
125.5 or 125.53 to 125.54 and 305.5 or 305.53 to 305.54 [3]
B2 for one correct angle
or B1 for –54.5 or –54.46… or for 2 angles with a difference of 180.
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