Mathematics · May / June 2020 · Paper 41 · Question 10
0580
As printed in the paper
Show the answer and mark scheme
10(a)(i)[3]
15.7 or 15.65... [3]
M2 for 2 2 ( 4 – 10) + (4 – –3) oe
or M1 for (–4 –10)2 + (4 – – 3)2 oe
10(a)(ii)[2]
– 10 4 – [= –2] oe 4 – – 3 10 = –2(–3) + c Or –4 = –2(4) + c and correct completion to y = –2x + 4 [2]
M1 A1
10(a)(iii)[4]
y = 1 2 x + 11 4 oe [4]
M1 for grad = ½ soi
M1 for [midpoint =] (½, 3)
M1 for substitution of (1/2, 3) into their y = mx + c oe
10(b)(i)[6]
1 22 − , − oe and (–5, 50) 3 27 [6]
B2 for 3x2 + 16x + 5
Or B1 for one correct
M1 for derivative = 0 or their derivative = 0
M1 for [x =] – 1 3 and [ x =] –5
B1 for – 22 27 and 50
10(b)(ii)[3]
1 22 − , − minimum 3 27 (–5, 50) maximum with correct reasons [3]
B2 for one correct with reason
or M1 for correct attempt e.g. 2nd derivatives, gradients or sketching
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