Mathematics · May / June 2020 · Paper 41 · Question 1
0580
As printed in the paper
Show the answer and mark scheme
1(a)(i)[2]
7680 [2]
M1 for 0.24 × 32 000 oe
1(a)(ii)[2]
34 240 [2]
M1 for 32 000 × 100 + 7 oe 100
1(b)[2]
5306.04 [2]
3 2
M1 for 5000 × + 1 oe 100
1(c)[4]
26.7 or 26.66... to 26.67 [4]
B3 for 96 or 96 360 oe OR
M3 for (1 − 1 5 ) × (1 −2 3 ) × 100 oe
or M2 for (1 − 1 5 ) and (1 −2 3 ) oe OR
M1 for 360 ÷ 5 [× 4] oe
M1 for their 288 ÷ 3 [× 2]
1(d)[2]
33 500 [2]
M1 for 36 515 ÷ 100 + 9 oe 100
1(e)[4]
6525 1.5 < h ⩽ 1.6 [4]
65 63 − [ ] =
M3 for A 290 oe 45 45 13 7
or M2 for − [ ] A = 290 oe 9 5
or M1 for correct attempt to convert to a common ratio value for Arjun or for 13 7 − oe 9 5
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