Mathematics · May / June 2020 · Paper 21 · Question 14
0580
As printed in the paper
Show the answer and mark scheme
14(a)[2]
[p = ] –13 [2]
M1 for 4(5x – 4) + 3 or better
14(b)[3]
3 1 x + 5 [3]
M2 for = y 3 1 + 1 = 3 x x , 5y = 3x + 1 or y − 5 5 5 5 –1 y , 3y = 5x − 1 or y + 1 3 = 5 x
M1 for = x 3 3
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