Computer Science · Oct / Nov 2016 · Paper 12 · Question 5
2210
As printed in the paper
The question as text
A computer uses an 8-bit register. The 8-bit register contains binary integers.
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5(a)[1]
112 [1]
5(b)[1]
56 [1]
5(c)[1]
divided by 2 // value 112 was halved // multiplied by 0.5 [1]
5(d)(i)[1]
0 0 0 0 1 1 1 0 [1]
5(d)(ii)[1]
14 [1]
5(e)[2]
Any two from:
– run out of places to the right of register / at the end of register – right-most 1 would be lost – number would become 3 instead of 3.5 – loss of precision [2]
0 0 0 0 1 1 1 0
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