Computer Science · May / June 2020 · Paper 22 · Question 3
0478
As printed in the paper
Show the answer and mark scheme
3(a)[4]
One mark for error and correction
Line 1 HighestMark ← 0
Line 7 INPUT Mark[Count]
Line 10 HighestMarkStudents ← HighestMarkStudents + 1
Line 14 HighestMark ← Mark[Count]
3(b)[6]
Any six from:
Add variable LowestMark …
… Set this to a high value for example 100
Add variable LowestMarkStudents …
… Set this to zero
Check if Mark[Count] = LowestMark …
… True – add 1 to LowestMarkStudents
Check if Mark[Count] < LowestMark …
… True – set LowestMarkStudenta to 1 and set LowestMark to Mark[Count]
Add extra output statement
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