Chemistry · Oct / Nov 2025 · Paper 42 · Question 6
0620
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The question as text
Compound E shown in Fig. 6.1 is an ester. CH3 CH2 CH2 CH2 CH3 O O C Fig. 6.1
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6(a)[1]
correctly circled ester link (including 2 C atoms and 2 O atoms)
6(b)[1]
ethyl butanoate
6(c)[1]
C3H6O
6(d)(i)[2]
M1 butanoic acid
M2 ethanol
6(d)(ii)[1]
acid
6(e)[1]
4
6(f)[1]
2C5H10O2 + 13O2 → 10CO2 + 10H2O
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