Chemistry · Oct / Nov 2025 · Paper 41 · Question 5
0620
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This question is about the homologous series of alcohols.
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5(a)(i)[1]
CnH2n+1OH
5(a)(ii)[1]
(same) functional group
5(b)(i)[6]
M1 25–35
M2 300
M3 yeast
M4 acid
M5 absence
M6 60 atm
of oxygen
5(b)(ii)[2]
C6H12O6 → 2C2H5OH + 2CO2
M1 C6H12O6 as the only reactant on left
M2 correct equation
5(b)(iii)[2]
C2H4 + H2O → C2H5OH
M1 both C2H4 + H2O only on left
M2 correct equation
5(c)(i)[1]
C4H10O2
5(c)(ii)[1]
2
5(d)(i)[1]
C2H3O2
5(d)(ii)[1]
hydrogen
5(e)(i)[3]
M1 any one correct fully displayed ester link between any two blocks
M2 three fully displayed inter-block ester links with correct orientation
M3 fully correct diagram showing two complete repeat units of polyester including continuation bonds
5(e)(ii)[1]
condensation (polymerisation)
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