Chemistry · May / June 2024 · Paper 42 · Question 3
0620
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The question as text
The symbol equation for the industrial production of ammonia is shown. N2(g) + 3H2(g) 2NH3(g) H = –90 kJ / mol
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3(a)[1]
Haber
3(b)[1]
enthalpy change (of reaction)
3(c)[3]
450 and °C
200 and atm or 20 000 and kPa
iron
3(d)[2]
M1 increase temperature
M2 increase pressure
3(e)[3]
M1 bond energy in breaking bonds
= [945 + (3 × 435)] = (+) 2250 (kJ / mol)
M2 = 2250 + 90 = 2340
M3 = 2340 / 6 = 390
3(f)(i)[1]
H2O
3(f)(ii)[1]
Ammonium chloride
3(f)(iii)[3]
M1 mol CaO = 1.12 / 56 = 0.02(00)
M2 mol NH3 = M1 × 2 = 0.02(00) × 2 = 0.04(00)
M3 vol NH3 = M2 × 24000 = 0.04 × 24000 = 960
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