Chemistry · May / June 2023 · Paper 41 · Question 2
0620
As printed in the paper
Show the answer and mark scheme
2(a)(i)[1]
N
2(a)(ii)[1]
B
2(a)(iii)[1]
F
2(a)(iv)[1]
C
2(a)(v)[1]
Li
2(a)(vi)[1]
Ne
2(b)(i)[2]
M1 different atoms of the same element with the same number of protons(1)
M2 different numbers of neutrons(1)
2(b)(ii)[2]
M1 10 × 20 +
11 ×80
( = 1080)(1)
M2 (1080 ÷ 100 =) 10.8(1)
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