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Chemistry · May / June 2020 · Paper 42 · Question 4

0620

As printed in the paper

The question as text

Oxygen is produced by the decomposition of hydrogen peroxide. Manganese(IV) oxide is the catalyst for this reaction.

Read automatically from the paper; the printed page above is exact.

Show the answer and mark scheme
  • 4(a)[2]

    substance that speeds up a reaction / increases rate (1)

    unchanged (chemically) at the end OR not used up OR lowers activation energy OR provides alternative pathway (1)

  • 4(b)[4]

    rate decreases (1)

    particles further apart / less particles per unit volume (1)

    fewer collisions per unit time / lower collision frequency (1)

    reaction stops because all hydrogen peroxide is used up

  • 4(c)[2]

    steeper gradient (1)

    reaches same volume of oxygen (1)

  • 4(d)[3]

    particles gain kinetic energy / particles move faster (1)

    greater number of collisions with activation energy (or more) / greater number of particles with activation energy (or more) / greater number of particles with energy required for reaction (1)

    more collisions are successful / more collisions are fruitful / more collisions lead to reaction (1)

  • 4(e)[3]

    48.0

    M1 moles of oxygen

    or moles of oxygen = 0.002 (1)

    24000

    M2 moles of hydrogen peroxide = M1 × 2 or moles of hydrogen peroxide = 0.004 (1)

    M3 concentration = M2 × 40 = 0.16 mol / dm3 (1)

    allow ECF

  • 4(f)[2]

    2KClO3 → 2KCl + 3O2

    ALL formulae correct (1)

    balancing (1)

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